多层次灰色评价法在科技计划项目绩效评估中的应用
评价与预测
2.5!"2"2.5""22.5""3"3"2.5D(2)=""3"3"3"2.5""2"3"#2!2"2"1.5"2.5"2.5""3"1"D(3)="2
"2"2"2.5"2.5""2"2.5"2.5#!2"2"2.5""2"3"2.5"1.5"(4)
D="2
2.5""2"2""2"2"1.5"#2
2221.52.5332332.522321.5222.52.52.511.522321.532.521.52232.51.51.52.522.52222
21.51.51.52.52.5322.5332.52322.51.5222.52.512.51.522.52222.51.51.521.5331.522.522.52.51.512
2.521.522.5332.52.532.522.52.52221.51.52.5312222.522.52.52.5221.51.532.51.52322.5221.52
21.51.522.52.53233322.52.521.51.52.522.52.511.51.522.52.51.52.52.51.51.52232.51.51.52.5222.51.51.52
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r(1)11为:
(1)(1)(1)
r111,,)(0.6087,r112r113=0.3913,0)可计算出r(1)r(1)r(1)r(1)r(1)r(1)r(1)12、13、31、33、21、23、41、从而得到项目X1的F1、F2、F3、F4、F5,(1)
(1)R(1)R(1)2、3、4和R5:
r(1)110.60870.39130!$!
(1)"r12%="0.47420.52580"%"
0.37620.50490.1189##r(1)13&r(1)21
!$!0.4490.5510$r(1)="0.66670.33330%"22%"%"%
(1)
0.60.40#&#&r23r(1)310.66670.33330!$!
r(1)="0.55320.44680"32%"%"
0.42420.51520.0606##r(1)33&
$
%%&
$
%%&
r(1)410.66670.33330$!$!(1)(1)R4="r42%="0.55320.44680%"%"%
(1)
0.47420.52580&#r43&#
r(1)51!$!0.4490.5510$R(1)r(1)="0.60870.39130%5="52%"%"%
(1)
0.40.60#&#&r53一级灰色综合评估
X1的F1、F2、F3、F4、F5作综合评B(1)B(1)B(1)B(1)B(1)1、2、3、4、5为:
(1)
(0.4788,0.482,0.0392) 1R1=(1)
(0.5753,0.4247,0) 2R2=(1)
(0.5721,0.4128,0.0151) 3R3=(1)
(0.5876,0.4124,0) 4R4=(1)
(0.4793,0.5207,0) 5R5=
(1)B(1)B(1)B(1)B(1)1、2、3、4、5得项目X1的总灰
R(1):
B1$!0.4788!(1)"B2%"0.5753
""(1)%B3=0.5721"(1)%"
0.5876B4%"""%"0.4793B(1)##5&
(1)
0.4820.0392$
%0.42470
%0.41280.0151%
0.41240%%0.52070&
X1的灰色综合评估结果B(1)为: (0.5504,R(1)=0.443,0.0066)C:C=不合格)(3,,故项目X1的=2,1)W(1)为:
(1)×CT=(0.5504,0.443,0.0066)(3,2,可计算项目X2、X3和X4的综合评、W(3)和W(4):
;W(3)=2.3382;W(4)=2.3513
2.4确定评估灰类
设评估灰类序号为e,其相应灰数及白化权函数如下:
“优”(e=1),设定灰数’1∈[3,第1灰类
,白化权函数为f(见图,白化权函数∞)1)1
62006
